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Article: <[email protected]>
From: [email protected](Nancy )
Subject: Re: PERTURBATIONS - the Zetas Explain
Date: 11 Jan 1997 20:09:26 GMT
In article <[email protected]>
> Now let's try this with unequal forces. The force on the
right
> (representing gravity) has 5lbs of force on it. The block on
the
> left (Repulsive force) is attached with a 3lbs spring. When
we
> release this block it will move to the right until a new
> equalibrium is found. It never comes back to it's original
> spot so it stays perturbed.
> [email protected] ()
Paul, the pre-perturbed planet could NOT be represented by a block with 5 lb. on one side and 3 lb. on the other, as it would NOT have been at equilibrium. You're description of equal forces is where the planets are where they have settled. They move toward the Sun, gravity being stronger than the repulsive force, until the repulsive force becomes equal to gravity. Exactly. You've got it!
In article <[email protected]>
> Let me suggest a more plausible analogy. If you have a block
> and on the right side we attach a spring with 5lbs of force.
The
> spring on the right by analogy represents the attractive
force of
> gravity. Next we add a spring on the left side of the block
with
> 5lbs of force. Since this spring operates in the opposite
direction
> this by analogy represents the opposite force of gravity now
> known to be your repulsive force and is operating in an
equal
> an opposite direction to the gravitational force.
>
> You can even perturb this system. Put you hand on the block
> and move it either left or right. After several wobbles it
comes
> back to the same spot. The net effect is zero. So we see
that only
> by having the repulsive force equal and opposite to the
gravitational
> force can we have a system that has no net effect on the
block.
> By analogy only an equal and opposite repulsive force can
bring
> planets that have been perturbed back to their original
orbits.
> [email protected] ()