Re: ZetaTalk and Spaceguard UK (D8)

In Article <[email protected]> Greg Neill wrote:
> In Article <[email protected]> Nancy Lieder wrote:
>> In Article  <[email protected]> Greg Neill wrote:
>>> The [6.67E-11 ] exponent is on the value for G, the
>>> gravitational CONSTANT.
>>
>> We have a gravitational CONSTANT?
>
> Newton's formula for the gravitational force between two masses:
>    F = G*M1*M2/r^2
> where G is the Gravitational constant, the constant of proportionality
> that makes the units all work out and sets the magnitude of the
> strength of the gravitational force.

Then lets plug that CONSTANT into both equations, which should come up
with the same VELOSITY for the Moon (which it won’t and Greg will go off
blustering).  Restated, then, the problem is to put it all on the same
page, using same units of measure for MASS per Mr. Tholen (who actually
works for NASA under various hand-off arrangements but won’t admit it).

The Moon's velosity should be:
   v = sqrt( G*M / r )
   v = sqrt( (Inverse Square) / 3.844E8) = ?
   v = sqrt( (G*M1*M2/r^2) / 3.844E8) = ?
   v = sqrt( (6.67E-11*5.9763e+24 kg * 7.3508e+22 kg / 3.844E8^2) / 3.844E8) = ?
 <============ RIGHT FORMULA FOR HIGH MASS MOON

 Where
       M1 = Earth = 5.9763e+24 kg
       M2 = Moon = 7.3508e+22 kg
        r = 200,000 miles = 3.844E8
        G = Gravity Constant of Earth = 6.67E-11

And where the force of gravity between two objects is another Newton
law:
        F = G*M1*M2/r^2

Should the velosity not be countering the force of gravity, to keep the
Moon from plunging to Earth? But it’s out there sedately poking along!
Floating up there!  Almost as though it were floating on .... a bed of
gravity particles jammed between the Earth and Moon, as in the REPULSION
FORCE!